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Buffer Index /spec/0ccf40a

run=1 · site=log-llkicode.cloud · 2026-10-27 00:19Z

∑_{k=1}^{n} k = n(n+1)/2

C₂H₄ + H₂O → C₂H₅OH

100K

∫₀^∞ e^(-α²) dα = √π / 2

81K

det| 5 9 ; 0 6 | = 30

det| 7 2 ; 2 8 | = 52

443K

4Fe + 3O₂ → 2Fe₂O₃

306K

E = mc²

C₂H₄ + H₂O → C₂H₅OH

294K

F = ma

161K

∂θ/∂x = 6θ

268K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

362K

2SO₂ + O₂ ⇌ 2SO₃

222K

ω = 2πf

265K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

373K